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Fix issue with collection disposal; increase precision in CSV reports

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This commit is contained in:
Alinson S. Xavier
2023-03-10 14:20:21 -06:00
parent 8432c49050
commit 7d4a763910
7 changed files with 29 additions and 29 deletions
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24
src/reports/plants.jl
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@@ -28,25 +28,25 @@ function plants_report(solution)::DataFrame
for (plant_name, plant_dict) in solution["Plants"]
for (location_name, location_dict) in plant_dict
for year = 1:T
capacity = round(location_dict["Capacity (tonne)"][year], digits = 2)
received = round(location_dict["Total input (tonne)"][year], digits = 2)
processed = round(location_dict["Process (tonne)"][year], digits = 2)
in_storage = round(location_dict["Storage (tonne)"][year], digits = 2)
utilization_factor = round(processed / capacity * 100.0, digits = 2)
energy = round(location_dict["Energy (GJ)"][year], digits = 2)
capacity = round(location_dict["Capacity (tonne)"][year], digits = 6)
received = round(location_dict["Total input (tonne)"][year], digits = 6)
processed = round(location_dict["Process (tonne)"][year], digits = 6)
in_storage = round(location_dict["Storage (tonne)"][year], digits = 6)
utilization_factor = round(processed / capacity * 100.0, digits = 6)
energy = round(location_dict["Energy (GJ)"][year], digits = 6)
latitude = round(location_dict["Latitude (deg)"], digits = 6)
longitude = round(location_dict["Longitude (deg)"], digits = 6)
opening_cost = round(location_dict["Opening cost (\$)"][year], digits = 2)
opening_cost = round(location_dict["Opening cost (\$)"][year], digits = 6)
expansion_cost =
round(location_dict["Expansion cost (\$)"][year], digits = 2)
round(location_dict["Expansion cost (\$)"][year], digits = 6)
fixed_cost =
round(location_dict["Fixed operating cost (\$)"][year], digits = 2)
round(location_dict["Fixed operating cost (\$)"][year], digits = 6)
var_cost =
round(location_dict["Variable operating cost (\$)"][year], digits = 2)
storage_cost = round(location_dict["Storage cost (\$)"][year], digits = 2)
round(location_dict["Variable operating cost (\$)"][year], digits = 6)
storage_cost = round(location_dict["Storage cost (\$)"][year], digits = 6)
total_cost = round(
opening_cost + expansion_cost + fixed_cost + var_cost + storage_cost,
digits = 2,
digits = 6,
)
push!(
df,